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Calculate the wave number for the longest wavelength transition in the...

Calculate the wave number for the longes | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

Calculate the wave number for the longest wavelength transition in the Balmer series of atomic hydrogen.

Answer:

According to Balmer formula

ṽ=1/λ = R_H[1/n₁²-1/n₂²]

For the Balmer series, n_i = 2.

Thus, the expression of wavenumber(ṽ) is given by,

Wave number (ṽ) is inversely proportional to wavelength of transition. Hence, for the longest wavelength transition, ṽ has to be the smallest.

For ṽ to be minimum, n_f should be minimum. For the Balmer series, a transition from n_i = 2 to n_f = 3 is allowed. Hence, taking n_f = 3,we get:

ṽ= 1.5236 × 10⁶ m^–1

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Comments

nani
2020-10-20 11:31:57

great

Musharraf Ahmed
2019-12-08 22:14:05

Thanks

Musharraf Ahmed
2019-12-08 22:13:29

Thanks

Unaiza
2019-10-02 19:31:06

Thnku it hepled a lot..

Ck sahu
2019-09-13 19:28:32

This is correct ans

Raghav Rai
2019-08-27 07:08:57

Wait then value is 1.097.isit right

Misti
2019-08-13 02:15:21

Very specific and precise answer .

Misti
2019-08-13 02:14:36

Thnx a lot...it was best last minute tip I ever recieved

K surya
2019-07-28 17:30:52

Change the background the answer was quite helpful

Dhriti
2019-07-07 19:08:32

salute to this question.

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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 17: Calculate the wave number for the longest wavelength transition in the Balmer series of atomic hydro....

Calculate the wave number for the longes | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

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