If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.
Diameter of carbon atom = 0.15nm = 0.15 x 10-9m = 1.5 x 10-10m
Length along which atoms are to be placed = 20cm = 20x10-2m = 2 x 10-1m
Therefore no of carbon atoms which can be placed along the length
= (2 x 10-1m) / (1.5x10-10 )
=1.33x109
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 35: If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be place....
Comments
I think thebmultiplication is wronh