Neon gas is generally used in the sign b | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate

(a) the frequency of emission,

(b) distance traveled by this radiation in 30 s

(c) energy of quantum and

(d) number of quanta present if it produces 2 J of energy.

Answer:

λ = 616nm  or = 616x10-9m

a) Frequency , v=c/ λ = 3.8x10/ 616x10-9 = 4.87x1014 s-1

b) Velocity of the radiation = 3x10m/s

Therefore distance travelled in 30s = 30x3x108 = 9.0x109m

c) E = hv = hc/ λ = (6.626x10-34)(3.0x108) / (616x10-9 ) = 32.27x10-20J

d) No of quanta in 2J of energy = 2/32.27 x 10-28 = 6.2x1018


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Comments

  • Rahmat Fatima
  • 2020-07-14 19:29:34

Thqs for this answers


  • Ankita
  • 2019-07-21 10:25:21

Thank you to S²


  • Ishita
  • 2019-07-01 20:32:11

Thanks for answering me


  • Ritik
  • 2019-06-29 10:41:43

Velocity of radiation ko velocity of light kyo liya


  • Rana
  • 2019-06-28 18:16:02

Thanks for this extraordinary app ☺


  • Jenish
  • 2019-06-18 22:00:27

Can you explain option (d) in detail


  • Kusum
  • 2019-06-09 22:14:15

Nice


  • Joy
  • 2019-06-07 12:34:39

Thanks


  • Jot
  • 2019-06-07 12:34:23

Thanks


  • Manvir singh
  • 2019-05-04 17:49:39

Frequency ma 10 ki power 16 kase ayi


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 47: Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the ....