The pH of 0.1M solution of cyanic acid ( | Class 11 Chemistry Chapter Equilibrium, Equilibrium NCERT Solutions

Question:

The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.

Answer:

c = 0.1 M

pH = 2.34

-log [H+] =  pH

-log [H+] = 2.34

[H+]  = 4.5 x 10-3

also

[H+]  = cα

4.5 x 10-3  =   0.1  α

α =  4.5 x 10-3  0.1

α  = 45 x 10-3 

Then,

Ka  =  cα2

= 0.1 (45 x 10-3)2

= 202.5 x  10-6

= 2.02 x 10-4

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Equilibrium.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 60: The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid....