The ejection of the photoelectron from t | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

Answer:

From the principle of conservation of energy, the energy of an incident photon (E) is equal to the sum of the work function (W0) of radiation and its kinetic energy (K.E) i.e.,

 

Energy of incident radiation(E)= hc/λ = (6.626x10-34)(3x108)/(256.7x 10-9)

= 7.74x10-19 J

 

Since the potential applied gives the kinetic energy to the radiation ,therefore K.E of the electron = 0.35Ev

 

Therefore work function = 4.83 – 0.35 = 4.48 eV


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Comments

  • Nihal
  • 2019-10-02 04:39:03

Conver 7.74 * 10^-19 J in eV to get 4.83.


  • Pooja
  • 2019-08-04 16:28:30

4.83 kaha se aya


  • Prabhat Kumar
  • 2018-09-28 11:38:56

See description on ncert solution


  • Ram
  • 2018-08-30 09:18:53

Please explain properly😠


  • mathivanan palraj
  • 2018-02-04 17:53:39

Volt cannot be converted into Joule without the value of Coulomb.


  • nishi
  • 2017-12-13 10:46:31

Therefore work function = 4.83 – 0.35 = 4.48 eV how did 4.83 come?


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 53: The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can b....