Emission transitions in the Paschen seri | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be represented as v = 3.29 × 1015 (Hz) [1/32 – 1/n2]

Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.

Answer:

V = c/λ = 3x108/1285x10-9

= 3.29 x 1015(1/32 – 1/n2)

= 1/n2 = 1/9 - 3x108/1285x10-9 x (1 / 3.29 x 1015)

= 0.111- 0.071 = 0.04 or 1/25

Or

n2 = 25,

n= 5

The spectrum lies in the infra-red region.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Structure of Atom.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

  • kingRB
  • 2020-05-22 18:04:34

Well done 👍👍✌✌👍👍✌✌👌👌👌👌👌👌👌👌☺☺☺☺☺☺☺☺☺☺☺☺


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 55: Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be repr....