The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105 ms–1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.
λ = h/mv
= 6.626x10-34 / (0.1)(4.37x105)
= 1.515x10-28m
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 60: The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105....
Comments
Its 10^-38
10^-38 not 10^-28 who edits the site?!
10 to the power -38 Not -28
10 to the power -38 is the answer not -28
It will be 10^-38 not 10^-28