Compare the relative stability of the fo | Class 11 Chemistry Chapter Chemical Bonding and Molecular Structure, Chemical Bonding and Molecular Structure NCERT Solutions

Question:

Compare the relative stability of the following species and indicate their magnetic properties:

O2,O2+,O2- (superoxide), O22-(peroxide)

Answer:

The stability of following species can be decided on the basis of bond order as follows:

O2 : KK

Bond order =1/2(Nb-Na)

= 1/2(8-4)

= 2 = Paramagnetic

 

Similarly, the electronic configuration of O2+ can be written as:

Bond order of  O2= 1/2(8-3)

= 2.5 = paramagnetic

 

Electronic configuration of O2- ion will be:

Bond order of = 1/2(8-5)

= 1.5 = paramagnetic

 

Electronic configuration of O22- ion will be:

Bond order of O22- =1/2(8-6) = 1  diamagnetic

 

The larger the bond order,greater is the stability

Therefore the stability decreases as O2> O2 > O2- > O22-.


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Comments

  • Siya koranga
  • 2020-03-17 12:29:27

Whats KK ?


  • rardSom
  • 2019-10-24 14:31:19

hi :) bross :)


  • varun Narayanan
  • 2018-03-03 10:39:24

How to identify para or dia magnet ic


  • ASDF
  • 2018-02-12 19:09:32

WASTE


  • Sandeep sohal
  • 2018-01-23 19:36:12

Very nice all answers i found in it


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 36: Compare the relative stability of the following species and indicate their magnetic properties: O....