Determine the molecular formula of an ox | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Q8.

Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively. Given that the molar mass of the oxide is 159.69 g mol–1.

From the available data Percentage of iron = 69.9

Percentage of oxygen= 30.1

Total percentage of iron & oxygen= 69.9+30.1= 100% 

 

Step 1 calculation of simplest whole number ratios of the elements

Element

Percentage

Atomic mass

Atomic ratio

Simplest ratio

Simplest whole no ratio

Fe

69.9

55.84

69.9/55.84=1.25

1.25= 1

2

O

30.1

16

30.1/16 = 1.88

1.88=1.5

3

 

Step 2  Writing the empirical formula of the compound

The empirical formula of the compound = Fe2 O3

 

Step 3 determination of molecular formula of the compound

 

Empirical formula mass = 2 X69.9 + 3 X16=187.8 amu

 

Molecular mass of oxide= 159.69g/mol(given)

Now we know molecular formula = n x Empirical formula

 

And n= molecular mass / empirical formula mass= 159.69/187.8 = 0.85 = approx 1

 

Therefore molecular formula = n x empirical formula

 

=1 x(Fe2O3) = Fe2O3

 

The molecular formula of the oxide is Fe2O3

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Important Questions & Answers

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This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

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What is the correct answer to: Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively. Given that the molar mass of the oxide is 159.69 g mol–1.?

From the available data Percentage of iron = 69.9

Percentage of oxygen= 30.1

Total percentage of iron & oxygen= 69.9+30.1= 100% 

 

Step 1 calculation of simplest whole number ratios of the eleme...

How do you solve Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively. Given that the molar mass of the oxide is 159.69 g mol–1. step by step?

Step-by-step explanation:
• From the available data Percentage of iron = 69
• 9

• Percentage of oxygen= 30
• 1

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Student Discussion

Siyara bhatt
Class · · , · Jul 13, 2019
Thank you so much!
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Siyara bhatt
Class · · , · Jul 13, 2019
Thank you so much!
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Prachi
Class · · , · Jul 03, 2019
Thanks... 😊
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Khusboo Chawla
Class · · , · Jun 16, 2019
Thank you everyone 🙏🙏🙏
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Shine
Class · · , · Jun 10, 2019
Not clear on empherical formula
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Hari
Class · · , · Apr 29, 2019
Empirical formula not clear
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Saba sindhi
Class · · , · Jan 18, 2019
New sem 2 text solution
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Akshatha
Class · · , · Nov 30, 2018
Thanks
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Tanaya Satange
Class · · , · Nov 29, 2018
Respected teacher,
You have taken the percentage of iron instead of the molar mass of iron while calculating the Empirical Formula mass.Thank you for making available such detailed answers to us.
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Aynal Hoque
Class · · , · Oct 22, 2018
In NCERT the molecular mass of oxide is not given....that's why I was in trouble to find the answer...thank's for this information..
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