Considering the elements B, C, N, F, and Si, the correct order of their non-metallic character is:
(a) B > C > Si > N > F
b) Si > C > B > N > F
(c) F > N > C > B > Si
d) F > N > C > Si > B
Boron is a p block element and is present in 13th group and 2nd period, carbon is a p block element and is present in 14th group and 2nd period, silicon is a p block element present in 14th group and 3rd period, nitrogen is p block element and belongs to 15th group and 2nd period while fluorine is also a p block element present in 17th group and 2nd period.The non-metallic character of elements increases from left to right across a period. Thus, the decreasing order of non-metallic character is F > N > C > B.Again, the non-metallic character of elements decreases down a group. Thus, the decreasing order of non-metallic characters of C and Si are C > Si. However, Si is less non-metallic than B i.e., B > Si. Hence, the correct order of their non-metallic characters is
F > N > C > B > Si.
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 39: Considering the elements B, C, N, F, and Si, the correct order of their non-metallic character is: ....
Comments
Silicon is a metalloid in 16th group of periodic table and how it possess non metallic nature and also boron has metallic character
Boron is a metalloid . how it can be more non metallic than silicon,a non metal.