Indicate the number of unpaired electron | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

Indicate the number of unpaired electrons in: (a) P, (b) Si, (c) Cr, (d) Fe and (e) Kr.

Answer:

(a) Phosphorus (P): 1s2 2s2 2p6 3s2 3p3

No of unpaired electron = 3

 

(b) Silicon (Si): 1s2 2s2 2p6 3s2 3p2

No of unpaired electron = 2 (since p orbital can have maximum 6 electron )

 

(c) Chromium (Cr): 1s2 2s2 2p6 3s2 3p6 4s1 3d5

No of unpaired electrons = 6 (since 1 electron is to be added to 4s & 5 electron to be added to 3d orbital.

 

(d) Iron (Fe): 1s2 2s2 2p6 3s2 3p6 4s2 3d6

No of unpaired electrons = 4

 

(e) Krypton (Kr): 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

Since all orbitals are fully occupied, there are no unpaired electrons in krypton.


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Comments

  • Saurav kumar chaturvedi
  • 2018-07-18 17:54:44

It is very good trick. But my question is that. What amount of cyclohexane will contain same number of bond as the number of unpaired electron in 16.42liter o Oxygen gas measured as 1.2 atmospheric pressure and 27°c


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 66: Indicate the number of unpaired electrons in: (a) P, (b) Si, (c) Cr, (d) Fe and (e) Kr.....