Comment on the thermodynamic stability o | Class 11 Chemistry Chapter Thermodynamics, Thermodynamics NCERT Solutions

Question:

Comment on the thermodynamic stability of NO(g), given

1/2 N2(g) + 1/2 O2(g) → NO(g) ; ΔrH0 = 90 kJ mol–1

NO(g) + 1/2 O2(g) → NO2(g) : ΔrH0= –74 kJ mol–1

Answer:

The positive value of ΔrH indicates that heat is absorbed during the formation of NO(g). This means that NO(g) has higher energy than the reactants (N2 and O2). Hence, NO(g) is unstable. The negative value of ΔrH indicates that heat is evolved during the formation of NO2(g) from NO(g) and O2(g). The product, NO2(g) is stabilized with minimum energy. Hence, unstable NO(g) changes to stable NO2(g).


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 21: Comment on the thermodynamic stability of NO(g), given 1/2 N2(g) + 1/2 O2(g) → NO(g) ; &Delt....