If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentrations of potassium, hydrogen and hydroxyl ions. What is its pH?
[KOH(aq)] = 0.561 / (1/5)g/L
= 2.805 g/L
= 2.805 x 1/56.11 M
= 0.05M
KOH(aq) → K+(aq) + OH-(aq)
[OH-] = 0.05M = [K+]
[H-] [H+] = Kw
[H+] Kw / [OH-]
= 10-14 / 0.05 = 2x10-13 M
∴ pH = 12.70
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 57: If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentra....
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