If 0.561 g of KOH is dissolved in water | Class 11 Chemistry Chapter Equilibrium, Equilibrium NCERT Solutions

Question:

If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentrations of potassium, hydrogen and hydroxyl ions. What is its pH?

Answer:

[KOH(aq)] = 0.561 / (1/5)g/L

= 2.805 g/L

= 2.805 x 1/56.11 M

= 0.05M

KOH(aq)  → K+(aq)  +  OH-(aq)

[OH-]  = 0.05M =  [K+]

[H-] [H+]  =  Kw

[H+] Kw / [OH-]

= 10-14 / 0.05 = 2x10-13 M

∴ pH = 12.70

 


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 57: If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentra....