Explain the following reactions
(a) Silicon is heated with methyl chloride at high temperature in the presence of copper;
(b) Silicon dioxide is treated with hydrogen fluoride;
(c) CO is heated with ZnO;
(d) Hydrated alumina is treated with aqueous NaOH solution
(a) When silicon reacts with methyl chloride in the presence of copper (catalyst) and at a temperature of about 537 K, a class of organo silicon polymers called methyl-substituted chlorosilanes (MeSiCl3, Me2SiCl2, Me3SiCl, and Me4Si) are formed.
(b) When silicon dioxide (SiO2) is heated with hydrogen fluoride (HF), it forms silicon tetrafluoride (SiF4). Usually, the Si-O bond is a strong bond and it resists any attack by halogens and most acids, even at a high temperature. However, it is attacked by HF.
SiO2 + 4HF → SiF4 + 2H2O
The SiF4 formed in this reaction can further react with HF to form hydrofluorosilicic acid.
SiF4 + 2HF → H2SiF6
(c) When CO reacts with ZnO, it reduces ZnO to Zn. CO acts as a reducing agent.
ZnO(s) + CO(g) → Zn(s) + CO2(g)
(d) When hydrated alumina is added to sodium hydroxide, the former dissolves in the latter because of the formation of sodium meta-aluminate.
Al2O3.2H2O + 2NaOH → 2NaAlO2 + 3H2O
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 21: Explain the following reactions (a) Silicon is heated with methyl chloride at high temperature in....
Comments