Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.
There are one octahedral hole for each atom in hexagonal close packed arrangement. If the no. of oxide ions per unit cell = 1.
then no. of fe3+ ions = 2/3 x octahedual holes
= 2/3 x 1 = 2/3
formula of the compound = fe2/3 O1 or fe2O3
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 19: Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every thre....
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