Calculate the mass of a non-volatile sol | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Calculate the mass of a non-volatile solute (molar mass 40 g mol-1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.

Answer:

Let the vapour pressure of pure octane be p10.

Then, the vapour pressure of the octane after dissolving the non-volatile solute is 80/100 p10 = 0.8 p10.

Molar mass of solute, M2 = 40 g mol - 1

Mass of octane, w1 = 114 g

Molar mass of octane, (C8H18), M1 = 8 × 12 + 18 × 1 = 114 g mol - 1

Applying the relation,

(p10 - p1) / p10    (w2 x M1 ) / (Mw1 )

(p10 - 0.8 p10) / p10    (w2 x 114 ) / (40  x 114 )

⇒ 0.2 p10 / p10   w2 / 40

⇒ 0.2 = w2 / 40

w2 = 8 g

Hence, the required mass of the solute is 8 g.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Solutions.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

  • Pankaj
  • 2019-05-24 11:24:16

Give the complete & correct solution, immediately


  • Tanya
  • 2019-05-04 12:11:11

This solution is quite easy but this is not correct. The correct answer for this question is 10.


  • Tanya
  • 2019-05-04 12:09:55

This is quite easy but correct answer is 10


  • Bhagya
  • 2019-04-25 10:54:30

For the answer to be 10 , it should be equated with X of solute i.e. ((w1/M1)/(w1/M1)+(w2/M2))


  • Gautam
  • 2019-04-22 22:21:37

Correct is 10


  • Neha
  • 2019-03-28 23:44:30

But answer is 10


  • Neha
  • 2019-03-28 23:43:03

Give the correct solution


  • Renuka
  • 2019-03-10 23:58:19

Answer is right


  • Malavika Manish
  • 2019-03-09 15:07:11

The answer is wrong ....the correct answer should be done like given below if vapour pressure of pure liquid is = Po 80 % of pure liquid Ps= 80×Po/100 = 0.8Po Ps =Po × Xsolute mass of solute = x gram mass of solvent = 114g Molar mass of solute= 40 g/mol Molar mass of solvent (octane C8H18) = 114g/mol Number of moles of solute = x/40 = 0.025x Number of moles of solvent = 114/114= 1 moles Mole fraction of solvent = 1/(1+0.025x) 0.8Po=Po×1/(1+0.025x) Cross multiply we get (1+0.025x))0.8Po= Po Divide by 0.8 Po we get 1+0.025x = 1.25 Subtract 1 both side we get 0.025x = 0.25 Now divide by 0.025 we get x = 10g


  • nikhil gupta
  • 2019-01-17 15:37:35

this answer in wrong instead the formula used will be p-ps/ps


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 18: Calculate the mass of a non-volatile solute (molar mass 40 g mol-1) which should be dissolved in 114....