The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
| Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate/mol L - 1 min - 1 |
| I | 0.1 | 0.1 |
2.0 × 10 - 2 |
| II | -- | 0.2 |
4.0 × 10 - 2 |
| III | 0.4 | 0.4 | -- |
| IV | -- | 0.2 |
2.0 × 10 - 2 |
The given reaction is of the first order with respect to A and of zero order with respect to B.
Therefore, the rate of the reaction is given by,
Rate = k [A]1[B]0
⇒ Rate = k [A]
From experiment I, we obtain
2.0 x 10-2mol L-1min-1= k (0.1 mol L-1)
⇒ k = 0.2 min-1
From experiment II, we obtain
4.0 x 10-2mol L-1min-1= 0.2 min-1[A]
⇒ [A] = 0.2 mol L-1
From experiment III, we obtain
Rate = 0.2 min-1 x 0.4 mol L-1
= 0.08 mol L-1min-1
From experiment IV, we obtain
2.0 x 10-2mol L-1min-1= 0.2 min-1[A]
⇒ [A] = 0.1 mol L-1
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 12: The reaction between A and B is first order with respect to A and zero order with respect to B. Fill....
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Sir aapka solution nahi samjh me aaya
Aapka solve samjh me nahi aaya sir
Nice but explain properly