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  • A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL-1, then what shall be the molarity of the solution?

A solution of glucose in water is labell | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Q5.

A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL-1, then what shall be the molarity of the solution?

10% w/w solution of glucose in water means that 10 g of glucose in present in 100 g of the solution i.e., 10 g of glucose is present in (100 - 10) g = 90 g of water.

Molar mass of glucose (C6H12O6) = 6 × 12 + 12 × 1 + 6 × 16 = 180 g mol - 1

Then, number of moles of glucose = 10 / 180 mol

= 0.056 mol

∴ Molality of solution = 0.056 mol / 0.09kg  = 0.62 m

Number of moles of water = 90g / 18g mol-1 = 5 mol

Mole fraction of glucose  (xg) = 0.056 / ( 0.056+5) = 0.011

And, mole fraction of water xw = 1 - xg

= 1 - 0.011 = 0.989

If the density of the solution is 1.2 g mL - 1, then the volume of the 100 g solution can be given as:

= 100g / 1.2g mL-1

= 83.33 mL

=83.33 x 10-3 L

∴ Molarity of the solution = 0.056 mol / 83.33 x 10-3 L

= 0.67 M

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What is the correct answer to: A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL-1, then what shall be the molarity of the solution??

10% w/w solution of glucose in water means that 10 g of glucose in present in 100 g of the solution i.e., 10 g of glucose is present in (100 - 10) g = 90 g of water.

Molar mass of glucose (C6H12O6) = 6 × 12 + 12...

How do you solve A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL-1, then what shall be the molarity of the solution? step by step?

Step-by-step explanation:
• 10% w/w solution of glucose in water means that 10 g of glucose in present in 100 g of the solution i
• e
• , 10 g of glucose is present in (100 - 10) g = 90 g of water

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Devanshi patkr
Class · · , · Jul 31, 2020
Thx for helping me 😊
👍 👎 Reply
Sonali
Class · · , · Jul 07, 2019
1000/90 can be written as 0.09
👍 👎 Reply
Sonali
Class · · , · Jul 07, 2019
1000/90 can be written as 0.09
👍 👎 Reply
Nazish
Class · · , · Jun 08, 2019
Why 19 was divided by 18.instead of 180
👍 👎 Reply
Amarjeet
Class · · , · May 24, 2019
From where 0.9 is there
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Viku
Class · · , · May 20, 2019
0.9 kha s aaya h
👍 👎 Reply
Monika
Class · · , · Mar 30, 2019
When we get 0.01
👍 👎 Reply
Abab
Class · · , · Mar 17, 2019
Hey
👍 👎 Reply
Aksh
Class · · , · Jan 06, 2019
What if density is not given
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Surendra singh kohli
Class · · , · Apr 25, 2018
Very interesting question
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