A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL-1, then what shall be the molarity of the solution?
10% w/w solution of glucose in water means that 10 g of glucose in present in 100 g of the solution i.e., 10 g of glucose is present in (100 - 10) g = 90 g of water.
Molar mass of glucose (C6H12O6) = 6 × 12 + 12 × 1 + 6 × 16 = 180 g mol - 1
Then, number of moles of glucose = 10 / 180 mol
= 0.056 mol
∴ Molality of solution = 0.056 mol / 0.09kg = 0.62 m
Number of moles of water = 90g / 18g mol-1 = 5 mol
Mole fraction of glucose (xg) = 0.056 / ( 0.056+5) = 0.011
And, mole fraction of water xw = 1 - xg
= 1 - 0.011 = 0.989
If the density of the solution is 1.2 g mL - 1, then the volume of the 100 g solution can be given as:
= 100g / 1.2g mL-1
= 83.33 mL
=83.33 x 10-3 L
∴ Molarity of the solution = 0.056 mol / 83.33 x 10-3 L
= 0.67 M
In a reaction between A and B, the initial rate of reaction (r0) was measured for different initial concentrations of A and B as given below:
|
A/ mol L - 1 |
0.20 | 0.20 | 0.40 |
|
B/ mol L - 1 |
0.30 | 0.10 | 0.05 |
|
r0/ mol L - 1 s - 1 |
5.07 × 10 - 5 |
5.07 × 10 - 5 |
1.43 × 10 - 4 |
What is the order of the reaction with respect to A and B?
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 5: A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction ....
Comments
Thx for helping me ð
1000/90 can be written as 0.09
1000/90 can be written as 0.09
Why 19 was divided by 18.instead of 180
From where 0.9 is there
0.9 kha s aaya h
When we get 0.01
Hey
What if density is not given
Very interesting question