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Henry's law constant for CO2 in water is 1.67 x 108Pa at 298 K. Ca...

Henry's law constant for CO2 in wate | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Henry's law constant for CO₂ in water is 1.67 x 10⁸Pa at 298 K. Calculate the quantity of CO₂in 500 mL of soda water when packed under 2.5 atm CO₂pressure at 298 K.

Answer:

It is given that:

K_H= 1.67 × 10⁸Pa

P_CO2= 2.5 atm = 2.5 × 1.01325 × 10⁵Pa

= 2.533125 × 10⁵Pa

According to Henry's law:

P_CO2= K_H^X

⇒ x = P_CO2 / K_H

= 2.533125 × 10⁵/ 1.67 × 10⁸

= 0.00152

We can write,

[Since, is negligible as compared to]

In 500 mL of soda water, the volume of water = 500 mL

[Neglecting the amount of soda present]

We can write:

500 mL of water = 500 g of water

=500 / 18 mole of water

= 27.78 mol of water

Now, n_CO2 / n_H2O = x

n_CO2 / 27.78 = 0.00152

n_CO2= 0.042 mol

Hence, quantity of CO₂in 500 mL of soda water = (0.042 × 44) g

= 1.848 g

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Comments

Tanbir Ahmed
2020-06-23 12:57:57

Very good platform

Priyanka Antil
2020-06-18 20:37:46

great explanation sir it was easy to understand..

Priyanka Antil
2020-06-18 20:37:13

easy to understand tq sir..it was superb u r such a great teacher..

Bhaskar Reddy
2020-03-28 12:17:49

Nice explanation

Anubhav kumar
2019-12-12 14:34:37

Can be defined (O)2 oxigen

Anshuman gupta
2019-11-21 20:19:21

Good explanation. thanks

IRONMAN
2019-10-14 21:23:21

Nice and T.K for ur ans.

Bhavesh
2019-10-14 10:25:47

If quantity is 500ml,will you not divide it by 2?

Amar
2019-07-21 09:30:27

Thanks nicely doneð

Chocolate boy
2019-06-16 15:53:56

Mind blowing answer ððð

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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 7: Henry's law constant for CO2 in water is 1.67 x 108Pa at 298 K. Calculate the quantity of CO2in ....

Henry's law constant for CO2 in wate | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

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