For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.
For a first order reaction, the time required for 99% completionis
t1 = 2.303/k Log 100/100-99
= 2.303/k Log 100
= 2x 2.303/k
For a first order reaction, the time required for 90% completion is
t2 = 2.303/k Log 100/100-90
= 2.303/k Log 10
= 2.303/k
Therefore, t1 = 2t2
Hence, the time required for 99% completion of a first order reaction is twice the time required for the completion of 90% of the reaction.
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 18: For a first order reaction, show that time required for 99% completion is twice the time required fo....
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