Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4
Molecules are made up of atoms & are quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.
(i) H2O:
The molecular mass of water, H2O
= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)
= [2(1.0084) + 1(16.00 u)]
= 2.016 u + 16.00 u
= 18.016
= 18.02 u
(ii) CO2:
The molecular mass of carbon dioxide, CO2
= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)
= [1(12.011 u) + 2 (16.00 u)]
= 12.011 u + 32.00 u
= 44.01 u
(iii) CH4:
The molecular mass of methane, CH4
= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)
= [1(12.011 u) + 4 (1.008 u)]
= 12.011 u + 4.032 u
= 16.043 u
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मà¥à¤ बताता हà¥à¤ ethene à¤à¥ à¤à¤²à¤¯à¥à¤à¤¨ सॠethanol à¤à¥ पà¥à¤°à¤¾à¤ªà¥à¤¤ à¤à¤°à¤¨à¥ à¤à¥ सबसॠठà¤à¥à¤à¥ à¤à¥à¤°à¤¿à¤¯à¤¾à¤µà¤¿à¤§à¤¿-"à¤à¤¬ ethene à¤à¤¾ à¤à¤²à¤¾à¤à¤¶à¤¨ ठमà¥à¤²à¥à¤¯ माधà¥à¤¯à¤® मà¥à¤ à¤à¤°à¤¾à¤¯à¤¾ à¤à¤¾à¤¯ तॠethanol बनता हà¥" C2H4 + H2O--â--= CH3CH2OH. In the presentation of H2SO4 Is reaction me -----line aero ko indicate karta hai mobile me aero ka sign nahin hua isliye aisa denote kar diye I am from bihar(begusarai).
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