Compare the stability of +2 oxidation state for the elements of the first transition series.
Sc | +3 | ||||||
Ti | +1 | +2 | +3 | +4 | |||
V | +1 | +2 | +3 | +4 | +5 | ||
Cr | +1 | +2 | +3 | +4 | +5 | +6 | |
Mn | +1 | +2 | +3 | +4 | +5 | +6 | +7 |
Fe | +1 | +2 | +3 | +4 | +5 | +6 | |
Co | +1 | +2 | +3 | +4 | +5 | ||
Ni | +1 | +2 | +3 | +4 | |||
Cu | +1 | +2 | +3 | ||||
Zn | +2 |
From the above table, it is evident that the maximum number of oxidation states is shown by Mn, varying from +2 to +7. The number of oxidation states increases on moving from Sc to Mn. On moving from Mn to Zn, the number of oxidation states decreases due to a decrease in the number of available unpaired electrons. The relative stability of the +2 oxidation state increases on moving from top to bottom. This is because on moving from top to bottom, it becomes more and more difficult to remove the third electron from the d-orbital.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 19: Compare the stability of +2 oxidation state for the elements of the first transition series.....
Comments
i have asked that which element is more stable in its +2 oxidation state