The conversion of molecules X to Y follo | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Question:

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

Answer:

The order of reaction is defined as the sum of the powers of concentrations In the rate law.

The rate of second order reaction can be expressed as     rate = k [A]2

The reaction X → Y follows second order kinetics.

Therefore, the rate equation for this reaction will be:

Rate = [X]2                                                    ________________________   (1)

Let [X] = a mol L-1 , then equation (1) can be written as:

Rate = k [a]2

ka2

If the concentration of X is increased to three times, then [X] = 3a mol L-1

Now, the rate equation will be:

Rate = k [3a]2

= 9 (ka2)

Hence, the rate of formation will increase by 9 times.


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Comments

  • ANSHIKA
  • 2020-05-31 11:15:53

Thanks...


  • Lycky
  • 2019-09-14 22:25:44

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  • Shalini kumari
  • 2019-07-08 19:48:19

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  • Diksha
  • 2019-07-07 07:16:56

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  • 2019-07-07 07:16:41

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  • Payal
  • 2019-05-27 18:56:45

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  • Radhe
  • 2019-05-13 12:18:02

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  • Bhola chhonker
  • 2019-05-11 08:26:45

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  • Bhola chhonker
  • 2019-05-11 08:26:18

Thanks


  • Diksha Mishra
  • 2019-04-22 02:19:06

Thnk u so much


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 4: The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased....