SELECT * FROM question_mgmt as q WHERE id=1841 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=59 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Chemical Kinetics the rate constant for the decomposition of n2o5 at

Question:

The rate constant for the decomposition of N2O5 at various temperatures is given below:

T/°C

 0 20 40 60 80

105 X K /S-1

0.0787 1.70 25.7 178 2140

Draw a graph between ln k and 1/T and calculate the values of A and Ea.

Predict the rate constant at 30 º and 50 ºC.

 

Answer:

From the given data, we obtain

T/°C 0 20 40 60 80

T/K

 273 293 313 333 353
1/T / k-1

3.66×10 - 3

3.41×10 - 3

3.19×10 - 3

3.0×10 - 3

2.83 ×10 - 3
105 X K /S-1 0.0787 1.70 25.7 178 2140
In k -7.147 -4.075 -1.359 -0.577 3.063

Slope of the line,

In k= - 2.8

Therefore, k = 6.08x10-2s-1

Again when T = 50 + 273K = 323K,

1/T = 3.1 x 10-3 K

In k = - 0.5

Therefore, k = 0.607 s-1

 


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