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the decomposition of hydrocarbon follows the equat...

Question:
The decomposition of hydrocarbon follows the equation

k = (4.5 x 10¹¹ s^-1) e^{-28000 K/T}

Calculate E_a.

Answer:

The given equation is

k = (4.5 x 10¹¹ s^-1) e^{-28000 K/T} (i)

Arrhenius equation is given by,

k= Ae^-E_a/RT(ii)

From equation (i) and (ii), we obtain

E_a/ RT = 28000K / T

⇒ E_a= R x 28000K

= 8.314 J K^{- 1}mol^{- 1}× 28000 K

= 232792 J mol ^{- 1}

= 232.792 kJ mol^{- 1}

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Question:
The decomposition of hydrocarbon follows the equation

k = (4.5 x 10¹¹ s^-1) e^{-28000 K/T}

Calculate E_a.

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Question: The decomposition of hydrocarbon follows the equation k = (4.5 x 1011 s-1) e-28000 K/T Calculate Ea.

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Question:
The decomposition of hydrocarbon follows the equation

k = (4.5 x 10¹¹ s^-1) e^{-28000 K/T}

Calculate E_a.