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Question:

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

Answer:

The order of reaction is defined as the sum of the powers of concentrations In the rate law.

The rate of second order reaction can be expressed as     rate = k [A]2

The reaction X → Y follows second order kinetics.

Therefore, the rate equation for this reaction will be:

Rate = k [X]2                                                    ________________________   (1)

Let [X] = a mol L-1 , then equation (1) can be written as:

Rate = k [a]2

= ka2

If the concentration of X is increased to three times, then [X] = 3a mol L-1

Now, the rate equation will be:

Rate = k [3a]2

= 9 (ka2)

Hence, the rate of formation will increase by 9 times.


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