A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57μm. Calculate the rate of emission of quanta per second.
(Given)Power of bulb, P = 25 Watt = 25 Js–1
We know, Energy of one photon, E = hν λ
Substituting the values in the given expression of E:
E = 34.87 × 10–20 J
Rate of emission of quanta per second is given by R = P/ E, Where R is the rate of emission, P is the power & E is the energy
Substituting the values in the equation we get
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 11: A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57μm. Calculate the rate of em....
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