Calculate the entropy change in surround | Class 11 Chemistry Chapter Thermodynamics, Thermodynamics NCERT Solutions

Question:

Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.

Answer:

It is given that 286 kJ mol-1of heat is evolved on the formation of 1 mol of H2O(l). Thus, an equal amount of heat will be absorbed by the surroundings.

qsurr = +286 kJ mol-1

Entropy change (ΔSsurr) for the surroundings =  qsurr / 7

= 286 kJ mol-1  / 298k

\therefore  ΔSsurr = 959.73 J mol-1K-1


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Comments

  • safia
  • 2019-03-13 01:58:03

in the above qusetion T does not given but in solution how it can be given to solve it


  • Palak
  • 2019-01-12 14:10:56

Great


  • ghanshyamsinh
  • 2018-09-07 13:39:41

calculate the bond enthalpy of HCl if enthalpy of H and Cl is 424 kj/mol and 230 kj/mol. the enthalpy of formation of HCl is -91 kj/mol


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 22: Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard condit....