The work function for caesium atom is 1. | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

The work function for caesium atom is 1.9 eV. Calculate

(a) the threshold wavelength and

(b) the threshold frequency of the radiation. If the caesium element is irradiated with a wavelength 500 nm, calculate the kinetic energy and the velocity of the ejected photoelectron.

Answer:

A) Work function of caesium (WO) = hvo

Therefore vo = WO/h = 1.9 x1.602 x10-19 / 6.626x10-34

= 4.59x1014/sec

 

B) λo =c/vo = 3x10/ 4.59x1014 = 6.54x10-7m

 

C) K.E of ejected electron = h(v-vo) = hc(1/λ – 1/ λo)

=(6.626x3x10-26) (1/500x10-9 – 1/654x10-9)

=(6.626x3x10-26) / 10-9(154/500x654)

= 9.36x10-20J

k.E = 1mv2/2 = 9.36x10-20J

=9.1x10-31/2 = 9.36x10-20J

Or

v2 = 20.55x1010m2s-2

Or

v = 4.53x105ms-1


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Comments

  • Vansh
  • 2019-12-19 05:59:26

Part 1st ka ans second wala h and vice versa


  • Jash
  • 2019-07-28 12:49:00

Thanks for providing the ans .😀😃


  • Mayukh
  • 2019-05-24 23:06:50

A really smart answer!


  • Khushi
  • 2019-01-24 19:48:31

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  • Garvit
  • 2018-07-10 17:27:02

Galat h


  • renu
  • 2018-07-06 15:58:42

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  • vijayvijay
  • 2018-06-16 12:36:03

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  • Khatri
  • 2018-05-27 21:41:55

Nyc solution


  • Rakshan
  • 2017-08-03 22:19:17

Bakwas


  • MHYT
  • 2017-06-15 19:26:04

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Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 51: The work function for caesium atom is 1.9 eV. Calculate (a) the threshold wavelength and (b) t....