Describe the change in hybridisation (if | Class 11 Chemistry Chapter Chemical Bonding and Molecular Structure, Chemical Bonding and Molecular Structure NCERT Solutions

Question:

Describe the change in hybridisation (if any) of the Al atom in the following reaction.

Answer:

Here in the given equation AlCl3 , Al is shifting its hybridization state from sp2 to sp3 because if we see the electronic configuration of Al it is [Ne] 3s2 3p1, i.e it has 3 electrons in its valence shell during ground state.In its excited state its one s orbital & two p orbitals will take part in hybridization to form sp2 hybrid orbital.

The orbital picture of aluminium in the excited state can be represented as:

Now according to the given reaction the product formed AlCl4- , will only be formed if its 3pz orbital is also filled by one electron in its excited state to form a sp3 hybrid orbital .therefore Al will shift its hybridization form sp2 to sp3 to form a tetrahedral shape


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Comments

  • Shakil Miah
  • 2019-05-21 11:43:14

1/2(3+4+1)=4=sp3


  • Vardhini
  • 2019-05-15 12:35:06

How can you find the hybridisation of alcl4- by using the shortcut formula? 1/2(v+M-c+A)= 1/2(3+4-1) =3=sp2 hybridisation?


  • Aditya
  • 2018-11-19 20:48:36

Change


  • Sandesh Goyal
  • 2018-08-18 22:08:50

So what is the final answer. .Change or no change


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 25: Describe the change in hybridisation (if any) of the Al atom in the following reaction.....