Describe the change in hybridisation (if any) of the Al atom in the following reaction.
Here in the given equation AlCl3 , Al is shifting its hybridization state from sp2 to sp3 because if we see the electronic configuration of Al it is [Ne] 3s2 3p1, i.e it has 3 electrons in its valence shell during ground state.In its excited state its one s orbital & two p orbitals will take part in hybridization to form sp2 hybrid orbital.
The orbital picture of aluminium in the excited state can be represented as:
Now according to the given reaction the product formed AlCl4- , will only be formed if its 3pz orbital is also filled by one electron in its excited state to form a sp3 hybrid orbital .therefore Al will shift its hybridization form sp2 to sp3 to form a tetrahedral shape
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 25: Describe the change in hybridisation (if any) of the Al atom in the following reaction.....
Comments
1/2(3+4+1)=4=sp3
How can you find the hybridisation of alcl4- by using the shortcut formula? 1/2(v+M-c+A)= 1/2(3+4-1) =3=sp2 hybridisation?
Change
So what is the final answer. .Change or no change