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If the speed of light is 3.0 × 108 ms–1, calculate the dis...

If the speed of light is 3.0 × 108 | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Question:

If the speed of light is 3.0 × 10⁸ ms^–1, calculate the distance covered by light in 2.00 ns.

Answer:

According to the question:

Time taken to cover the distance = 2.00 ns

= 2.00 × 10^–9 s

Speed of light = 3.0 × 10⁸ ms^–1

We know speed = distance/time

Or distance = speed x time

Therefore Distance travelled by light in 2.00 ns

= Speed of light × Time taken

= (3.0 × 10⁸ ms ^–1) (2.00 × 10^–9 s)

= 6.00 × 10^–1 m

= 0.600 m

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Comments

Shreya
2020-05-10 21:49:57

Thanks for the solution but what is na here.

Ujjwal Chaurasia
2019-11-16 20:12:46

Thanks for confirmation

Shahtab
2019-10-03 20:01:43

What is ns here?

Umar
2019-08-08 12:25:13

Thanks alot

Aman Gupta
2019-08-05 18:53:08

Thanks

Teena
2019-05-05 18:25:27

Wow

Prakhar Crazy
2018-08-04 22:02:19

Thanks

Sahil
2018-06-14 20:24:49

Thnks for sugesation

Navneet singh
2018-05-08 21:53:13

thanks alot

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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 22: If the speed of light is 3.0 × 108 ms–1, calculate the distance covered by light in 2.00....

If the speed of light is 3.0 × 108 | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

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