What will be the pressure of the gaseous | Class 11 Chemistry Chapter States of Matter, States of Matter NCERT Solutions

Question:

What will be the pressure of the gaseous mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1L vessel at 27°C?

Answer:

From the equation Pv = n RT for the two gases. We can write

0.8 x 0.5 = nH2 x RT  or nH2  = 0.8 x 0.5 / RT

ALSO  0.7 x 2.0  = n02 . RT  or n02  = 0.7 x 2 / RT

When introduced in 1 L vessel, then

Px1L = (n02 + nH2)  RT

Putting the values, we get

P = 0.4 + 1.4 = 1.8 bar

Hence, the total pressure of the gaseous mixture in the vessel is 1.8 bar


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Comments

  • Jitendra Yadav
  • 2019-12-04 22:54:56

Osm work.... Thanks a lot.... 🙏🙏🙏


  • Akash soni
  • 2018-12-02 21:45:31

Very good Amazing


  • Yo
  • 2018-09-28 00:24:22

Value of nh2 nd no2


  • Harsh rao
  • 2018-09-05 22:41:55

Who are xyz just stuppied


  • Xyz
  • 2018-01-18 21:25:04

What's the value of The here?


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 8: What will be the pressure of the gaseous mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen a....