One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,
H2O (g) + CO (g) ↔ H2 (g) + CO2 (g)
Calculate the equilibrium constant for the reaction.
The given reaction is:
H2O (g) + CO (g) ↔ H2 (g) + CO2 (g)
Initial Concentration: 1/10 M 1/10 M 0 0
At equilibrium 1-0.4/10 M 1-0.4/10 M 0.4/10M 0.4/10M
= 0.06M 0.06M 0.04M 0.04M
Therefore, the equilibrium constant for the reaction,
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 14: One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% ....
Comments