Given the standard electrode potentials, | Class 11 Chemistry Chapter Redox Reactions, Redox Reactions NCERT Solutions

Question:

Given the standard electrode potentials,

K+/K = -2.93V, Ag+/Ag = 0.80V,

Hg2+/ Hg = 0.79V

Mg2+/ Mg = -2.37V. Cr3+/ Cr = -0.74V

Arrange these metals in their increasing order of reducing power.

Answer:

The lesser the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cr < Mg < K.


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 29: Given the standard electrode potentials, K+/K = -2.93V, Ag+/Ag = 0.80V, Hg2+/ Hg = 0.79V Mg....