Given the standard electrode potentials,
K+/K = -2.93V, Ag+/Ag = 0.80V,
Hg2+/ Hg = 0.79V
Mg2+/ Mg = -2.37V. Cr3+/ Cr = -0.74V
Arrange these metals in their increasing order of reducing power.
The lesser the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cr < Mg < K.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 29: Given the standard electrode potentials, K+/K = -2.93V, Ag+/Ag = 0.80V, Hg2+/ Hg = 0.79V Mg....
Comments