A solution is obtained by mixing 300 g o | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4

Answer:

Molecules are made up of atoms & are  quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus  molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.

(i) H2O:

The molecular mass of water, H2O

= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)

= [2(1.0084) + 1(16.00 u)]

= 2.016 u + 16.00 u

= 18.016

= 18.02 u

(ii) CO2:

The molecular mass of carbon dioxide, CO2

= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)

= [1(12.011 u) + 2 (16.00 u)]

= 12.011 u + 32.00 u

= 44.01 u

(iii) CH4:

The molecular mass of methane, CH4

= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)

= [1(12.011 u) + 4 (1.008 u)]

= 12.011 u + 4.032 u

= 16.043 u


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Comments

  • Shriniwas Kshirsagar
  • 2020-09-04 16:57:04

Thnx sir


  • Viku
  • 2019-05-20 22:11:20

But finally percentage is 64.5%


  • Sanyam jain
  • 2019-04-30 22:44:01

Please correct that Percentage of H2O in final solution is 66.5 % not 65.5 %


  • Sanyam jain
  • 2019-04-30 22:43:23

Please correct that Percentage of H2O in final solution is 66.5 % not 65.5 %


  • Sumbul
  • 2019-04-29 22:25:24

Thanks


  • siddharth
  • 2019-04-26 06:08:51

thnx sir


  • preeti mahato
  • 2019-04-23 21:16:10

Thanks sir for this answer, this answer will help me a lot


  • Mayank
  • 2019-04-17 09:04:29

Thanks


  • Annu
  • 2019-04-14 11:42:59

If percentage composition in terms of mass is asked


  • Annu
  • 2019-04-14 11:42:33

If percentage composition in terms of mass is asked


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 7: A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate ....