Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.
For hydrogen electrode, , it is given that pH = 10
∴[H+] = 10 - 10M
Now, using Nernst equation:
= - 0.0591 log 1010
= - 0.591 V
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 4: Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.....
Comments
Because electrodes potential is a intensive property
Why we have taken reduction?
thankuuu
Why you did not multiple both side by 2?