Henry's law constant for the molality of methane in benzene at 298 Kis 4.27 x 105 mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.
As we know that
p = k x c
We have given p = 760 mm, k = 4.27 x 105
Putting the given values in equation
760 = 4.27 x 105 x c
Or
c = 760 / 4.27x 105
c = 178 x 10-5
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 35: Henry's law constant for the molality of methane in benzene at 298 Kis 4.27 x 105 mm Hg. Calcula....
Comments
Bt p=kx where x is mole fraction,not solubility
i think wrong b/c solubility=k*p
The answer is correct....177.98x10-5=178x10-5
Wrong answer