Henry's law constant for the molalit | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Henry's law constant for the molality of methane in benzene at 298 Kis 4.27 x 105 mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.

Answer:

As we know that

p = k x c

We have given p = 760 mm, k = 4.27 x 105

Putting the given values in equation

760 = 4.27 x 105 x c

Or

c = 760 / 4.27x 105

c = 178 x 10-5


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Comments

  • Reena
  • 2019-12-15 19:50:30

Bt p=kx where x is mole fraction,not solubility


  • aditya
  • 2019-06-20 23:42:14

i think wrong b/c solubility=k*p


  • Scarlet
  • 2019-04-19 19:34:07

The answer is correct....177.98x10-5=178x10-5


  • Ganesh
  • 2019-02-26 11:52:14

Wrong answer


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 35: Henry's law constant for the molality of methane in benzene at 298 Kis 4.27 x 105 mm Hg. Calcula....