Determine the amount of CaCl2 (i = 2.47) | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.

Answer:

We know that

π = i n/V RT

π = i w/MV iRT

w = πMV /  iRT     .......................(1)

Now we have given below values:

π =  0.75 atm

V = 2.5L

i = 2.47

T = (27+273) K = 300K

Here,

R = 0.0821L atm k-1 mol-1

M = 1x40 + 2x35.5

= 111 g/mol

Now putting the value in equation 1:

w =  0.75x111x2.5 / 2.47x0.0821x300

=3.42g

Hence, the required amount of CaCl2 is 3.42 g.


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Comments

  • Mohit
  • 2019-12-10 22:13:32

It is really helpful.....


  • Adi
  • 2019-06-19 22:14:04

nice site


  • Soju
  • 2019-05-24 13:31:51

Put the value of R=8.314 instead of putting 0.0821 ,then will get the right answer that is 0.03mol.


  • Aryan raaz
  • 2019-04-16 11:48:07

But sir NCERT me to answer 0.03 mol de rha hai Is answer se to 0.003 mol aa rha hai Kya karu


  • Kaushik
  • 2019-04-08 19:39:19

Good site.Has each answer.


  • Sourabh
  • 2019-02-26 00:17:43

I help this answer


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 40: Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic press....