Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of water at 25° C, assuming that it is completely dissociated.
If K2SO4 is completely dissociated then these ions are produced
Then K2SO4 = 2K+ + SO42-
So total number of ions produced = 3
Therefore I =3
Now molecular mass of K2SO4 = 2 x 39 + 1 x 32 + 4 x 16 = 174 g/mol
Now π = I Crt
= I WB X RT / MB X V
= 3 X 25 X 10-3 X 0.082 X 298 / 174 X 2
= 5.27 X 10-3 atm.
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 41: Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of wat....
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