Determine the osmotic pressure of a solu | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of water at 25° C, assuming that it is completely dissociated.

Answer:

If K2SO4 is completely dissociated then these ions are produced

Then K2SO4 = 2K+ + SO42-

So total number of ions produced = 3

Therefore I =3

Now molecular mass of K2SO4 = 2 x 39 + 1 x 32 + 4 x 16 = 174 g/mol

Now π = I Crt

= I WB X RT / MB X V

= 3 X 25 X 10-3 X 0.082 X 298  /  174 X 2

= 5.27 X 10-3 atm.


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Comments

  • bhupakhi kalita
  • 2020-09-08 13:10:16

parfact answer


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 41: Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of wat....