Gold (atomic radius = 0.144 nm) crystall | Class 12 Chemistry Chapter The Solid State, The Solid State NCERT Solutions

Question:

Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?

Answer:

We know, for a fcc unit cell,radius of atom

r = a/2√2

Or

a = 2r√2

By putting the values of r &√2 we get

a = 2 x 0.144 x 1.414 = 0.407nm


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Comments

  • Aman
  • 2019-03-02 13:46:01

Thank🙏💕


  • Aman
  • 2019-03-02 13:45:15

Thanks🙏🙇


  • Rahul
  • 2018-05-26 20:34:06

Can u also find density


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 21: Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a si....