Calculate the osmotic pressure in pascal | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.

Answer:

It is given that:

Volume of water, V= 450 mL = 0.45 L

Temperature, T = (37 + 273)K = 310 K

Number of moles of the polymer,

n = 1 / 185000 mol

We know that:

Osmotic pressure, 

 

= 1/185000 mol X 1/0.45L X 8.314 X 103 Pa L K-1mol-1 X 310K 

 

= 30.98 Pa = 31 Pa (approximately)


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Comments

  • Arushi
  • 2019-05-05 19:20:45

After solving the numerical value the ans given is not coming


  • Yatin
  • 2019-04-28 20:38:02

How is the value 10^3 came with the value of R


  • Yatin
  • 2019-04-28 20:37:29

How is the value 10^3 came with the value of R


  • Aashwin
  • 2019-04-05 20:59:33

R=8.314JK^(-1)=8.314×10^3 PaL-1K-1


  • raghava
  • 2019-03-28 20:57:34

good,ok one of the best


  • Cherian
  • 2019-02-13 22:59:33

How that 10 ^3 came with 8.314


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 12: Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of poly....