The rate of the chemical reaction double | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Q8.

The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.

It is given that T1 = 298 K

∴T2 = (298 + 10) K

= 308 K

We also know that the rate of the reaction doubles when temperature is increased by 10°.

Therefore, let us take the value of k1 = k and that of k2 = 2k

Also, R = 8.314 J K - 1 mol - 1

Now, substituting these values in the equation:

= 52897.78 J mol - 1

= 52.9 kJ mol - 1

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  • Read the question carefully and focus on the core concept being asked.
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Important Questions & Answers

What is the correct answer to: The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.?

It is given that T1 = 298 K

∴T2 = (298 + 10) K

= 308 K

We also know that the rate of the reaction doubles when temperature is increased by 10°.

Therefore, let us take the value of k1 = k and that o...

How do you solve The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea. step by step?

Step-by-step explanation:
• It is given that T1 = 298 K
•
• ∴T2 = (298 + 10) K
•
• = 308 K

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Aj
Class · · , · Aug 27, 2019
Very nice
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Poorvansh
Class · · , · May 18, 2019
Very good
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Awabit
Class · · , · Mar 05, 2019
straight forward easy to understand. Thanks a million times
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Hitarth Soni
Class · · , · Nov 20, 2018
Thank you so much.
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Aynal Hoque
Class · · , · Oct 23, 2018
Thanks a lot
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Harsh
Class · · , · Sep 23, 2018
Easy to understand
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Baljit kaur
Class · · , · Jun 13, 2018
very very helpful
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