The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.
It is given that T1 = 298 K
∴T2 = (298 + 10) K
= 308 K
We also know that the rate of the reaction doubles when temperature is increased by 10°.
Therefore, let us take the value of k1 = k and that of k2 = 2k
Also, R = 8.314 J K - 1 mol - 1
Now, substituting these values in the equation:
= 52897.78 J mol - 1
= 52.9 kJ mol - 1
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 8: The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K....
Comments
Very nice
Very good
straight forward easy to understand. Thanks a million times
Thank you so much.
Thanks a lot
Easy to understand
very very helpful