The rate of the chemical reaction double | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Question:

The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.

Answer:

It is given that T1 = 298 K

∴T2 = (298 + 10) K

= 308 K

We also know that the rate of the reaction doubles when temperature is increased by 10°.

Therefore, let us take the value of k1 = k and that of k2 = 2k

Also, R = 8.314 J K - 1 mol - 1

Now, substituting these values in the equation:

= 52897.78 J mol - 1

= 52.9 kJ mol - 1


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Comments

  • Aj
  • 2019-08-27 12:47:50

Very nice


  • Poorvansh
  • 2019-05-18 20:41:20

Very good


  • Awabit
  • 2019-03-05 09:26:24

straight forward easy to understand. Thanks a million times


  • Hitarth Soni
  • 2018-11-20 11:01:54

Thank you so much.


  • Aynal Hoque
  • 2018-10-23 10:35:57

Thanks a lot


  • Harsh
  • 2018-09-23 00:12:32

Easy to understand


  • Baljit kaur
  • 2018-06-13 17:37:40

very very helpful


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 8: The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K....