Given the standard electrode potentials,
K+/ K = - 2.93V,
Ag+/ Ag = 0.80V,
Hg2+ / Hg = 0.79V
Mg2+ / Mg = - 2.37 V,
Cr3+ / Cr = - 0.74V
Arrange these metals in their increasing order of reducing power.
The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of
K+/ K < Mg2+ / Mg < Cr3+ / Cr < Hg2+ / Hg < Ag+ / Ag.
Hence, the reducing power of the given metals increases in the following order:
Ag < Hg < Cr < Mg < K
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 2: Given the standard electrode potentials, K+/ K = - 2.93V, Ag+/ Ag = 0.80V, Hg2+ / Hg ....
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