Given the standard electrode potentials, | Class 12 Chemistry Chapter Electrochemistry, Electrochemistry NCERT Solutions

Question:

Given the standard electrode potentials,

K+/ K = - 2.93V, 

Ag+/ Ag = 0.80V,

Hg2+ / Hg = 0.79V

Mg2+ / Mg = - 2.37 V,

Cr3+ / Cr = - 0.74V

Arrange these metals in their increasing order of reducing power.

Answer:

The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of

K+/ K < Mg2+ / Mg < Cr3+ / Cr < Hg2+ / Hg < Ag+ / Ag.

Hence, the reducing power of the given metals increases in the following order:

Ag < Hg < Cr < Mg < K


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 2: Given the standard electrode potentials, K+/ K = - 2.93V,  Ag+/ Ag = 0.80V, Hg2+ / Hg ....