The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm-1. Calculate its molar conductivity.
Given, k = 0.0248 S cm - 1
c = 0.20 M
Molar conductivity, Am = (k x 1000) / c
= 0.0248 x1000 / 0.20
124 Scm2 mol - 1
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 8: The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm-1. Calculate its molar conductivit....
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