Calculate (a) molality (b) molarit | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4

Answer:

Molecules are made up of atoms & are  quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus  molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.

(i) H2O:

The molecular mass of water, H2O

= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)

= [2(1.0084) + 1(16.00 u)]

= 2.016 u + 16.00 u

= 18.016

= 18.02 u

(ii) CO2:

The molecular mass of carbon dioxide, CO2

= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)

= [1(12.011 u) + 2 (16.00 u)]

= 12.011 u + 32.00 u

= 44.01 u

(iii) CH4:

The molecular mass of methane, CH4

= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)

= [1(12.011 u) + 4 (1.008 u)]

= 12.011 u + 4.032 u

= 16.043 u


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Comments

  • Gaganpreet
  • 2019-06-17 17:13:16

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  • 2019-06-02 11:19:17

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  • 2019-05-27 18:18:51

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  • 2019-05-27 18:18:12

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  • Naincy
  • 2019-05-22 18:03:40

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  • 2019-05-02 22:24:31

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  • Shubham pandey
  • 2019-04-20 13:04:00

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  • Yuvraj
  • 2019-04-04 21:51:09

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  • Aditya Raj Chauhan
  • 2019-03-28 00:16:15

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  • Nixon MJ
  • 2019-03-09 17:32:24

Thanks


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Calculate (a) molality (b) molarity and (c) mole fraction of KI if the density of 20% (m....