The molar conductivity of 0.025 mol L-1 | Class 12 Chemistry Chapter Electrochemistry, Electrochemistry NCERT Solutions

Question:

The molar conductivity of 0.025 mol L-1 methanoic acid is

46.1 S cm2 mol-1.

Calculate its degree of dissociation and dissociation constant. Given λ0(H+)

= 349.6 S cm2 mol-1 and  λ0(HCOO-) = 54.6 S cm2 mol

Answer:

C = 0.025 mol L - 1

Now, degree of dissociation:

Thus, dissociation constant:


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: The molar conductivity of 0.025 mol L-1 methanoic acid is 46.1 S cm2 mol-1. Calculate its degr....