How do you explain the absence of aldehy | Class 12 Chemistry Chapter Biomolecules, Biomolecules NCERT Solutions

Q3.

How do you explain the absence of aldehyde group in the pentaacetate of D-glucose?

D-glucose reacts with hydroxylamine (NH2OH) to form an oxime because of the presence of aldehydic (-CHO) group or carbonyl carbon. This happens as the cyclic structure of glucose forms an open chain structure in an aqueous medium, which then reacts with NH2OH to give an oxime.

 

But pentaacetate of D-glucose does not react with NH2OH. This is because pentaacetate does not form an open chain structure.

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Important Questions & Answers

What is the correct answer to: How do you explain the absence of aldehyde group in the pentaacetate of D-glucose??

D-glucose reacts with hydroxylamine (NH2OH) to form an oxime because of the presence of aldehydic (-CHO) group or carbonyl carbon. This happens as the cyclic structure of glucose forms an open chain structure in an aqueo...

How do you solve How do you explain the absence of aldehyde group in the pentaacetate of D-glucose? step by step?

Step-by-step explanation:
• D-glucose reacts with hydroxylamine (NH2OH) to form an oxime because of the presence of aldehydic (-CHO) group or carbonyl carbon
• This happens as the cyclic structure of glucose forms an open chain structure in an aqueous medium, which then reacts with NH2OH to give an oxime


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This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

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Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Sairaj mane
Class · · , · Mar 13, 2019
Very good explanation
I liked it
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Sorry
Class · · , · May 10, 2018
Well explained 👍🏻
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