Welcome to the NCERT Solutions for Class 12 Biology - Chapter Organisms and Population. This page offers a step-by-step solution to the specific question from Exercise 1, Question 6: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
A population grows exponentially if sufficient amounts of food resources are available to the individual. Its exponential growth can be calculated by the following integral form of the exponential growth equation:
Nt = No ert
Where,
Nt= Population density after time t
NO= Population density at time zero
r = Intrinsic rate of natural increase
e = Base of natural logarithms (2.71828)
From the above equation, we can calculate the intrinsic rate of increase (r) of a population.
Now, as per the question,
Present population density = x
Then,
Population density after two years = 2x
t = 3 years
Substituting these values in the formula, we get:
⇒ 2x = x e3r
⇒ 2 = e3r
Applying log on both sides:
⇒ log 2 = 3r log e
Hence, the intrinsic rate of increase for the above illustrated population is 0.2311.
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Comments
Thank you so much
Thank youð
It's value of e not of loge 0.434 is nothing but value of loge
Sir can u tell me log e value is 2.7 nd log 3 is 0.4 bt here 3 * 0.434 why?
Thanks a lot ð
yupp i did the same...
The ârâis the specific growth rate ( dN/Ndt ) when population growth is exponential. ( Population becomes 2 from 1 in three years. dN= 2, N=1 and dt = 3 ) By putting the values we get 2/ 1x3 = 0.66, it is so simple