Why is the highest oxidation state of a | Class 12 Chemistry Chapter The d-and f-Block Elements, The d-and f-Block Elements NCERT Solutions

Question:

Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?

Answer:

The oxidation state of an element is related to the number of electrons that an atom loses, gains, or appears to use when joining with another atom in compounds. It also determines the ability of an atom to oxidize (to lose electrons) or to reduce (to gain electrons) other atoms or species. Oxidation results in an increase in the oxidation state. Reduction results in a decrease in the oxidation state.  If an atom is reduced, it has a higher number of valence shell electrons, and therefore a higher oxidation state, and is a strong oxidant. For example, oxygen (O) and fluorine (F) are very strong oxidants.Both oxide and fluoride ions are highly electronegative and have a very small size. Due to these properties, they are able to oxidize the metal to its highest oxidation state.


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Comments

  • Abhishek Sharma
  • 2018-10-31 08:24:00

This is long type but we find out these ans in short plz


  • rotik
  • 2018-03-12 11:20:24

Try to write short answer


  • Shreya Rathor
  • 2018-03-10 12:51:38

You should launch a app so that all NCERT questions can be seen easily ✏


  • Alefiya
  • 2016-03-06 10:36:45

The answers for the last few questions ain't here.....can u plz get them.... A kind request


  • saqib najar
  • 2016-02-03 08:09:44

answer plz


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?....