SELECT * FROM question_mgmt as q WHERE id=1726 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=57 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Solutions determine the osmotic pressure of a solution prepa

Question:

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of water at 25° C, assuming that it is completely dissociated.

Answer:

If K2SO4 is completely dissociated then these ions are produced

Then K2SO4 = 2K+ + SO42-

So total number of ions produced = 3

Therefore I =3

Now molecular mass of K2SO4 = 2 x 39 + 1 x 32 + 4 x 16 = 174 g/mol

Now π = I Crt

= I WB X RT / MB X V

= 3 X 25 X 10-3 X 0.082 X 298  /  174 X 2

= 5.27 X 10-3 atm.


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